Question

Lim➡️3 (3-x)^2/(x-3)

Answer 1

`\boxed{\lim_(x\to 3)((3-x)^2)/((x-3)) =0}`

Explanation:

`\lim_(x\to 3)((3-x)^2)/((x-3))`

`\lim_(x\to 3)((3-x)^2)/(-(-x+3))`

`\lim_(x\to 3)((3-x)(3-x))/(-(-x+3))`

Cancel the same factor

`\lim_(x\to 3)-(3-x)`

`\lim_(x\to 3)(-3+x)`

Now, once as
`x \rightarrow 3`,

`\lim_(x\to 3)(-3+x)=0`

Answer 2

if the limit is three then ans is zero and if limit is -3 then ans is -6

Explanation:

it may help you to understand