Question

What is the solution of the system x+2y+3z=6; y+2z=0; z=2

Answer 1

z=2, y=-4, x=8

Explanation:

since we know z is 2, we can plug it back into the equation to find y:

y+2*2=0

first, simplify:

y+4=0

then, subtract 4 from both sides:

y=-4

now we know what both z and y are, we can put the values back into the equation to find x:

x+2(-4)+3*2=6

first, simplify:

x-8+6=6

x-2=6

then, add 2 to both sides:

x=8

so the values are:

z=2, y=-4, x=8