82.8k views
0 votes
The equation

(k + 3) x^2+ 6x + k = 5, where k is a constant,
has two distinct real solutions for x.
Show that k satisfies
k^2– 2k – 24 < 0

1 Answer

5 votes

Answer:

Get an answer for 'The equation(k+3)x^2+6x+k = 5, where k is a constant, has two distinct real solutions for x.Show that k satisfies k^2-2k-24<0' and find ...Step-by-step explanation:

User Prajila V P
by
4.5k points