Explanation:
Hey there!
The sequences are; 8,13,18,23.....
Common difference (d)= 5
Use formula: tn = t1+(n-1)d
Where d is the common difference and t1 is first sequence.
Or, tn = 8 + (n-1)5
= 8+5n -5
= 5n +3.
Therefore the required nth term is; tn = 5n+3.
Check;
1st term (t1) = 8 = 5×1+3=8 (true)
2nd term (t2) = 13 = 5×2+3=13 (true)
3rd term (t3)= 18 = 5×3+3=18 (true)
4th term (t4) = 23 = 5×4+3=23 (true).
Hope it helps..