Question

URGENT PLEASEEEE, WILL GIVE 100 POINTS

Laughing gas, N2O can be turned into smog NO2 by heating the laughing gas in the presence of oxygen. _____N2O + _____O2 -->_____NO2
If 9.00 grams of laughing gas react. How many moles of oxygen react?

If 7.50 grams of oxygen react, how many grams of smog are produced?

Answer 1

2N₂O + 3O₂ ⇒ 4NO₂

mol N₂O = 9 g : 44 g/mol = 0.205

mol O₂ = 3/2 x 0.205 = 0.3075

mass O₂ = 0.3075 x 32 g/mol = 9.84 g

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mol O₂ = 7.5 g : 32 g/mol = 0.234

mol NO₂ (smog) = 4/3 x 0.234 = 0.312

mass NO₂ = 0.312 x 46 g/mol = 14.352 g

Answer 2

Let's balance

• 2N_2O+3O_2---->4NO_2

Moles of laughing gas

• 9/44
• 0.2mol

2 moles need 3 mol O_2

1 mol needs= 1.5mol O_2

moles of O_2.

• 1.5(0.2)
• 0.3mol

#2

• 3 molO_2 produces 4 mol smog
• 1 mol produces 4/3=1.3mol smog

Moles Of O_2

• 7.5/32
• 0.2mol

Moles of smog

• 1.3(0.2)=0.26mol

Mass

• 0.26(46)
• 11.96g