Question

CuCl2(aq) + NaOH(aq) right-arrow Cu(OH)2(s) + NaCl(aq) what is the ionic equation and net ionic equation ?

Answer 1

The net ionic equation for the reaction of CuCl2(aq) with NaOH(aq) is Cu²⁺(aq) + 2OH⁻(aq) → Cu(OH)₂(s), where the sodium and chloride ions are spectator ions and are omitted from the net ionic equation.

Step-by-step explanation:

To address the reaction of CuCl2(aq) + NaOH(aq) → Cu(OH)2(s) + NaCl(aq), let's first write the balanced molecular equation, complete ionic equation, and net ionic equation.

Molecular equation:

CuCl₂(aq) + 2NaOH(aq) → Cu(OH)₂(s) + 2NaCl(aq)

Complete ionic equation:

Cu²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + 2OH⁻(aq) → Cu(OH)₂(s) + 2Na⁺(aq) + 2Cl⁻(aq)

Net ionic equation:

Cu²⁺(aq) + 2OH⁻(aq) → Cu(OH)₂(s)

In the net ionic equation, the sodium (Na⁺) and chloride (Cl⁻) ions are spectator ions and do not participate in the reaction, hence they are omitted from the net ionic equation. The actual chemical change involves the copper (II) cation reacting with hydroxide ions to form copper (II) hydroxide as a precipitate.

Answer 2

Reactions are given below.

Step-by-step explanation:

Chemical equation:

CuCl₂ + NaOH → Cu(OH)₂ + NaCl

Balanced Chemical equation:

CuCl₂(aq) + 2NaOH(aq) → Cu(OH)₂(s) + 2NaCl(aq)

Ionic equation:

Cu²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + 2OH⁻(aq) → Cu(OH)₂(s) + 2Na⁺(aq) + 2Cl⁻ (aq)

Net ionic equation:

H⁺(aq) + OH⁻(aq) → H₂O(l)

The Cl⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The Cu(OH)₂ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.