Question

Sin(6x-10) = cos(4x+10)
I need to solve for x so I can then solve the rest..

Answer 1

steps below

Explanation:

Trig property: if Sin A = Cos B, Sin A = Sin (π/2 - B)

sin(6x-10) = cos(4x+10)

sin (6x-10) = sin (π/2 - (4x+10))

6x-10 = π/2 - (4x+10) + 2nπ

6x-10 = π/2 - 4x - 10 + 2nπ

10x = (1+4n)/2 * π

`x = ((1+4n)\pi )/(20) \\n=1 \\x = (5\pi )/(20) = (1)/(4) \pi \\n=2 \\x = (9)/(20) \pi \\.........`

or x = 45° , 81°, 117° .......