Answer:
∠AXC = 46°
∠BXC = 23°
Explanation:
If XB is the angle bisector of ∠AXC then XB bisects ∠AXC t at X. Hence;
∠AXC = ∠AXB+∠BXC and ∠AXB= ∠BXC
The equation becomes
∠AXC = ∠AXB+∠AXB
∠AXC = 2∠AXB
Given
m∠AXB=23°
Substitute the given angle into the expression above to get ∠AXC since we are not told what to find but we can as well find ∠AXC
∠AXC =2(23)
∠AXC = 46°
Also note that since ∠AXB= ∠BXC, then ∠BXC will be 23°