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A young sumo wrestler decided to go on a special diet to gain weight rapidly. WWW represents the wrestler's weight (in kilograms) after ttt months. W=80+5.4tW=80+5.4tW, equals, 80, plus, 5, point, 4, t What was the wrestler's weight before his special diet?

2 Answers

5 votes

Answer:

10.8

Explanation:

This is correct on khan academy.

User Merrin K
by
8.0k points
5 votes

Answer:

80kg

Explanation:

Given:

W = 80 + 5.4t

Where,

W = the wrestler's weight (in kilograms

t = number of months

What was the wrestler's weight before his special diet?

W = 80 + 5.4t

When t = 0 (that is before the weight gain)

W = 80 + 5.4t

= 80 + 5.4(0)

= 80kg

When t = 1 ( first month of the weight gain)

W = 80 + 5.4t

= 80 + 5.4(1)

= 80 + 5.4

= 85.4 kg

The wrestler's weight before his special diet is 80kg

ALTERNATIVELY

W = 80 + 5.4t

80 = the fixed weight

5.4 = weight gained per month

t = number of months

Therefore,

The fixed weight which is 80kg is the weight of the wrestler before the special diet.

User AsymLabs
by
7.6k points
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