Question

Find the 14th term of the geometric sequence 5 -10 20

Answer 1

Well since the person above me explained it already it’s that answer

Answer 2

a14 = -40,960

Explanation:

The sequence has a first term of 5 and a common ratio of -10/5 = -2, so the n-th term is given by ...

an = a1·r^(n-1)

an = 5·(-2)^(n-1)

The 14th term is then ...

a14 = 5·(-2)^(14-1) = -5·2^13 = -5·8192

a14 = -40,960