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If 65.85g of N2 are placed in 17.5L container, the pressure is 1988 mmHg. What is the temperature of the gas?

User JackoM
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1 Answer

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Answer: The temperature of the gas if 65.85g of N2 are placed in 17.5L container with a pressure of 1988 mmHg is 1780. 6° C

Step-by-step explanation:

The ideal gas law states that the volume, pressure and temperature of the a gas is related to the number of moles.

It is represented thus;

P V = n R T

Parameters :

Pressure, P = 1988 mmHg

Volume, V = 17.5 L

number of moles, n = mass ÷ molar mass

mass of N2 = 65.84g

Molar mass of N2 = 28.02 g/ mol

n = 65.85 ÷ 28.02

n = 2. 350 moles.

Temperature = ?

Universal gas constant, R = 8.314 J/mol. K

Calculations :

T = P V ÷ n R

T = 1988 × 17.5 ÷ 2.350 × 8.314

T = 34790 ÷ 19. 5379

T = 1780. 6 ° C

Thus, the temperature of the gas is 1780. 6 ° C

User Procatmer
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