Question

What is an equation of the line that passes through the points (3,6) and (−3,4)?

Answer 1

y = x/3 +5

Explanation:

Step1 : finding the slope

m =
`(y2-y1)/(x2-x1)`

(3,6) and (−3,4)

m =
`(4-6)/(-3-3)`

m = 1/3

Solving for the equation

y-y1 = m(x-x1) , (3,6)

y-6 = 1/3(x-3)

y = x/3 -1 +6

y = x/3 +5