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Solve by Completing the Square: x2 + 8x + 6 = 0

User Henderunal
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1 Answer

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Answer:

X2+8X+6=0

We add all the numbers together, and all the variables

X^2+8X+6=0

a = 1; b = 8; c = +6;

Δ = b2-4ac

Δ = 82-4·1·6

Δ = 40

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

X1=−b−Δ√2aX2=−b+Δ√2a

The end solution:

Δ−−√=40−−√=4∗10−−−−−√=4√∗10−−√=210−−√

X1=−b−Δ√2a=−(8)−210√2∗1=−8−210√2

X2=−b+Δ√2a=−(8)+210√2∗1=−8+210√2

Explanation:

User Ihor Dobrovolskyi
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