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What is the midpoint of np if N(10, -14) and P(-16, -4)?

User YuriyP
by
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1 Answer

1 vote

Answer:

Midpoint = (-3 ,-9)

Explanation:


\\Midpoint =\left((x_2+x_1)/(2),\:\:(y_2+y_1)/(2)\right)\\\\\left(x_1,\:y_1\right)=\left(10,\:-14\right),\:\\\left(x_2,\:y_2\right)=\left(-16,\:-4\right)\\\\=\left((-16+10)/(2),\:(-4-14)/(2)\right)\\\\=((-6)/(2), (-18)/(2)\\ \\Simplify\\\\=\left(-3,\:-9\right)

User Logisima
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