Question

Solve the equation. X^5-5x^3+4x=0

Answer 1

0, +/- 1. +/- 2

Explanation:

`x^(5) -5x^(3) +4x=0` Write the equation in the form of P(x) = 0.

`x(x^(4) - 5x^(2) + 4) = 0` Factor out the GCF, x.

`x(x^(2))^(2) - 5x^(2) + 4 = 0` Factor
`(x^(2))^(2)- 5x^(2) + 4 = 0`.

`x = 0,`
`(x^(2))^(2) - 5x^(2) + 4 = 0` Let a =
`x^(2)` and substitute.

`a^(2) - 5a + 4 = 0` Factor.

`(a - 4)(a - 1) = 0` Replace a with
`x^(2)`.

`(x^(2) - 4)(x^(2) -1) = 0` Factor
`(x^(2) - 4)` as a difference of squares.

`(x -2)(x+2)(x^(2) -1) = 0` Use the Zero Product Property

`x = 2, x = -2, x^(2) = -1`

`x = 0, 1, -1, 2, -2`

Answer 2

Wait

Explanation:

Is a equation or polynomial