Question

the value of a varies directly at the square of the value of b, and b=3 when a=10. find the value of a when b=9

Answer 1

answer = 90

Explanation:

General equation: a = k*b^2

Specifically: 10 = k*(3)^2 = 9 k

Solving for k: k = 10/9

Then a = (10/9)b^2. If b = 9, then a = (10/9)(9)^2 = 90 (answer)