Find the equation in standard form of the parabola passing through the giving points. (-1,0) (0,3) (1,2)

Question

asked Apr 15, 2021 137k views

1 Answer

Shivam Agrawal · Answer 1 · 2021-04-19T22:53:26+0000

Let y = ax²+bx+c then substitute all of orders. we'll be doing equations system.

$a-b+c=0\\c=3\\a+b+c=2$

Ok we are at this.

Substitute c = 3 into equation 1 and equation 3.

$a-b+3=0\\a-b=-3$

$a+b+3=2\\a+b=2-3\\a+b=-1$

then addition and subtract for a-b = 3 and a+b = -1

$a-b=-3\\a+b=-1\\2a=-4\\a=-2$

Therefore a = -2, substitute a = -2 in a-b+c=0 or a+b+c=2 but i'm doing a-b+c=0 one.

$a-b+c=0\\\\-2-b+3=0\\-b+1=0\\-b=-1\\b=1$

Therefore b = 1, substitute both a, b and c into y=ax²+bx+c as we get,

y=-2x^2+x+3 #