Question

Nehal is a real estate developer, and he is designing a new neighborhood. The neighborhood will have four streets, each of which is three-fourths of a mile long. He will divide each street into lots and build one house on each lot. In order to comply with building codes, each lot much have at least 65 feet frontage along the street. What is the maximum number of houses can he build in his new neighborhood?

Answer 1

240 houses

Explanation:

Given that:

Number of streets = 4

Length of each street = 3/4 miles long

Street is divided into lots with one house built per lot

1 mile = 5289 feets

3/4 miles = (3/4) * 5280 = 3960 feets

Hence, street is 3960 feets long

Since each lot must have at least 65 feet frontage along the street:

Number of lots per street :

Length of street / frontage length

3960 ft / 65 ft = 60.92

Hence, maximum number of lots per street = 60 lots per street

Maximum number of houses in New neighborhoods :

Number of lots per street × number of streets

= 60 × 4

= 240 houses