Question

The endpoints of PQ are at P (-4,-2) and Q (6,3). What are the coordinates of point S which divides PQ such that PS: SQ is equal to 3:2?

Answer 1

The coordinates are (2,1)

Explanation:

We use the internal division formula here;

x,y) = (nx1 + mx2)/(m + n) , (ny1 + my2)/(m + n)

Where;

m = 3 and n = 2

x1 = -4 , x2 = 6

y1 = -2 , y2 = 3

Substituting these values;

(x,y) = (2(-4) + 3(6))/(3 + 2) , (2(-2) + 3(3))/(2+3)

= (10/5 , 5/5)

= (2,1)