Question

Three potential employees took an aptitude test. Each person took a different version of the test. The scores are reported below.

Demetria got a score of 71.471.4; this version has a mean of 66.666.6 and a standard deviation of 88.

Norma got a score of 258.3258.3; this version has a mean of 238238 and a standard deviation of 2929.

Kaitlyn got a score of 88; this version has a mean of 7.27.2 and a standard deviation of 0.40.4.

If the company has only one position to fill and prefers to fill it with the applicant who performed best on the aptitude test, which of the applicants should be offered the job?

Answer 1

The job should be offered to Kaitlyn

Explanation:

From the question we are told that

The data for Demetria is

Test score is 71.4

The mean is 66.6

The standard deviation is 8

Generally the z-sore for Demetria is mathematically evaluated as

`z - score = ( 71.4 - 66.6 )/( 8)`

= >
`z - score = 0.6`

The data for Norma is

Test score is 258.3

The mean is 238

The standard deviation is 29

Generally the z-sore for Norma is mathematically evaluated as

`z - score = ( 258.3 - 238 )/( 29)`

= >
`z - score = 0.7`

The data for Kaitlyn is

Test score is 8

The mean is 7.2

The standard deviation is 0.4

Generally the z-sore for Norma is mathematically evaluated as

`z - score = ( 8 - 7.2)/( 0.4)`

= >
`z - score = 2`

Now given that the z-score of Kaitlyn is the highest it means that performed best and should be given the job