Answer:
(a):1680J
(b):579.6J
(c):366800J/kg
Step-by-step explanation:
like I said first consider that heat lost= heat gained this will vary with what you are given in the question eg here you equate heat lost by the water at 50 to the heat gained by ice and melted ice
so
heat lost by water=heat gained by ice+heat gained by melted ice
using the formula Q=mc∆thiter and Q=mlf( lf is latent heat of fusion for ice)
mc∆thiter=mlf+mc∆thiter
{convert all given units to SI units}
(a)0.1×4200×{46-50}=1680
(b):Q=mc∆thiter
0.003×4200×{46-0}=579.6
(c):mc∆thiter=mlf+mc∆thiter
1680=0.003lf+579.6
1680-579.6=0.003lf
1100.4=0.003lf
lf=366800J/kg