Answer:
17822
Explanation:
The number that are divisible by 7 between 30 and 500 are as follows :
35, 42,49,.....,497
It will form an AP with first term, a = 35 and common difference, d = 7
Let there are n terms in the AP.
nth term of an AP is given by :

Putting all the values,

Now, the sum of n terms of an AP is given by :
![S_n=(n)/(2)[2a+(n-1)d]](https://img.qammunity.org/2021/formulas/mathematics/high-school/nbbqumcy0s5kebc4qw68eqqy1qlvhszlv2.png)
Putting all the values,
![S_n=(67)/(2)[2(35)+(67-1)7]\\\\S_n=17822](https://img.qammunity.org/2021/formulas/mathematics/college/5ygeu5pp572xx7tjedv6nuxxbarbwnmjb3.png)
Hence, the sum of the numbers that are divisible by 7 between 30 and 500 is 17822.