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Work out length of AB

Work out length of AB-example-1
User AndyJ
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AB is 2√137 in simplest form

or 23.4 rounded to the nearest tenth.
User RagtimeWilly
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\huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }


\large\underline{ \boxed{ \sf{✰\:Note }}}

★ 1st let's know what is the given figure is and it's related concepts for solving !

➣ Given Triangle is a right angled triangle

➣ It is having 3sides let's know what are the name of these sides

➣ 1st AB is know as hypotenuse

➣ 2nd AC and is called Base of the triangle

➣ 3rd BC whích is know as perpendicular of the triangle

➣ Hypotenuse(H):-The side of a right triangle opposite the right angle.

➣ Perpendicular(P):- Exactly upright; extending in a straight line.

➣ Base(B):- it also known as the side opposite to hypotenuse

➣Perpendicular and base are know as the leg of right angled triangle

➣ We can easily find length of one missing side by using a theorem name as "Pythagorean theorem"

➣ Pythagorean theorem :- A mathematical theorem which states that the square of the length of the hypotenuse of a right triangle is equal to the sum of the squares of those of the two other sides

★ Note :- The Pythagorean theorem only applies to right triangles.


\rule{70mm}{2.9pt}

★ Writing this theorem mathematically ★


{ \boxed{✫\underline{ \boxed{ \sf{Pythagorean \: theorem \: ⇒ {Hypotenuse }^2={ Base }^2+ {Height }^2}}}✫}}

★ Here ★

➣ Base (AC)= 22cm

➣ Perpendicular (height) (BC)= 8cm


\rule{70mm}{2.9pt}

✝ Assumption ✝

➣ let Hypotenuse ( AB ) = "x"


\boxed{ \rm{ \pink ➛AB^2= AC^2+BC^2}}


\rule{70mm}{2.9pt}

✝ let's substitute values ✝


\rm{ \pink ➛x^2=22 ^2+8^2} \\ \rm{ \pink ➛x^2 = 484+ {64} } \\ \rm{ \pink ➛ {x}^(2) = 548 } \\ \rm{ \pink ➛= {x} = √(548) } \\ \rm{ \pink ➛ x = 2√(137) \: or23.4} \\


\rule{70mm}{2.9pt}

Hence Hypotenuse (AB) in the given triangle is of


{ \boxed{✛\underline{ \boxed{ \sf{2√(137) \: or23.4\green✓}}}✛}}


\rule{70mm}{2.9pt}

Hope it helps !

User Sobutterysosmooth
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