Question

Determine how many grams of solute and solvent you would need to prepare 225 g of 11.9%

NaCl solution.​

Answer 1

`m_(solute)=26.8g`

Step-by-step explanation:

Hello.

In this case, since the definition of by-mass percent is:

`\%m/m=(m_(solute))/(m_(solution))*100\%`

Whereas we know the percent as 11.9 % and the mass of the solution as 225g, so we compute the grams of solute as follows:

`m_(solute)=(\%m/m*m_(solution))/(100\%)\\ \\m_(solute)=(11.9\%*225g)/(100\%)\\ \\m_(solute)=26.8g`

Best regards.