Final answer:
To find the amount in a family's savings account after 2 years with a principal of $40,000 and a 10% per annum interest rate compounded half-yearly, the compound interest formula is used, resulting in $48,620.25 at the end of 2 years.
Step-by-step explanation:
A family saved $40,000 in a savings bank that pays compound interest half-yearly at a rate of 10% per annum. To calculate the amount in the family's account at the end of 2 years, we use the formula for compound interest:
A = P(1 + r/n)^nt
Where:
A is the amount of money accumulated after n years, including interest.
P is the principal amount (the initial amount of money).
r is the annual interest rate (decimal).
n is the number of times that interest is compounded per year.
t is the time the money is invested for, in years.
In this case, P = $40,000, r = 10/100 = 0.10, n = 2 (since the interest is compounded half-yearly), and t = 2 years.
Plugging these values into the formula, we get:
A = 40,000(1 + 0.10/2)^2*2
A = 40,000(1 + 0.05)^4
A = 40,000 * (1.05)^4
A = 40,000 * 1.21550625
A = $48,620.25
Therefore, the amount in the family's account at the end of 2 years is $48,620.25.