Question

The pressure inside a sealed container of methane gas (CH) is 35.0 kPa. If this 80.0 L sample of

methane is increased to a pressure of 92.0 kPa, what is the new volume?
Show work pls

Answer 1

The answer is 30.43 L

Step-by-step explanation:

In order to find the new volume we use the formula for Boyle's law which is

`P_1V_1 = P_2V_2`

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the new volume

`V_2 = (P_1V_1)/(P_2) \\`

From the question

P1 = 35 kPa = 35000 Pa

V1 = 80 L

P2 = 92 kPa = 92000 Pa

So we have

`V_2 = (35000 * 80)/(92000) = (2800000)/(92000) \\ = 30.43478260...`

We have the final answer as

30.43 L

Hope this helps you