Question

X^2=6x+1

1) rewrite the equation by completing the square

2) what are the solutions to the equation?

Answer 1

x=+-√10+3

Explanation:

x^2=6x+1

x^2-6x=1

To create a trinomial square on the left side of the equation, find a value that is

equal to the square of half of b

a is the number next to x^2

b is the number next to x

c is the last number

b is -6

half of b is -3

square of half of b is 9

put 9 on both sides of the = sign

x^2-6x+9=1+9

x^2-6x+9=10

(x-3)^2=10

take the square root of both sides of the = sign

√(x-3)^2=√10

x-3=√10

x=+-√10+3