Answer:
![\huge\boxed{15.3 \ \text{gallons}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/rgnjrladrha7nkubwf3yuyxtyc2xzir6kd.png)
Explanation:
We know that Chang drove 420 miles on 18 gallons of gas.
This can be represented as a ratio,
.
![(420)/(18)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ojl519s9wj0iri3hz8ltpu3ls47wo1apbg.png)
We can also represent 357 miles over an unknown gas quantity as a ratio.
![(357)/(x)](https://img.qammunity.org/2021/formulas/mathematics/high-school/zio90gd7a8jvgbwtv1k0gt0twctqgz9kkp.png)
Since he uses a proportional amount of gas to his miles, we can set these two proportions equal to each other to find the value of x.
![(420)/(18) = (357)/(x)](https://img.qammunity.org/2021/formulas/mathematics/high-school/gf8oyuixng25hudvbwff0vitx2nahib9vh.png)
To find the value of x, we can use the cross products property.
![357 \cdot 18 = 6426\\\\6426 / 420 = 15.3](https://img.qammunity.org/2021/formulas/mathematics/high-school/yf60odnj2l13q02hf70y45x1x92n4q1on4.png)
So he needs 15.3 gallons of gas to drive 357 miles.
Hope this helped!