Question

Dentify which graph can be used to solve each equation. Enter the letter of the correct graph next to the equation.

On a coordinate plane, a parabola opens up in quadrant 1. It has a vertex at (3, 0).  
x4 + 3 = 0 On a coordinate plane, a function has 3 turning points. The function goes down in quadrant 2 to (negative 2, 0) and then goes up to (0, 10). The function then goes down again to (2, 0) and then increases. 
(x − 3)4 = 0 On a coordinate plane, a parabola opens up and has a vertex at (0, 3).

Answer 1

first one is C

second is A

third is B

Explanation:

Answer 2

Graph A is a choice. y = x + 3 is the right equation.

To further elaborate on the reasoning behind our choice of graph A, let's delve into the characteristics of the equation y = x + 3.

This linear equation implies that the y-value is always equal to the sum of the x-value and 3.

This linear relationship manifests in graph A, where the line intercepts the x-axis at (-3, 0), coinciding with the value of x that satisfies the equation.

In contrast, graphs B and C deviate from the linear relationship represented by graph A.

Graph B depicts a parabolic curve, while graph C resembles a quadratic function. These curves fail to align with the linear nature of the equation y = x + 3.

Therefore, graph A, with its straight line depiction and a precise x-intercept at (-3, 0), stands as the unequivocal choice for representing the equation y = x + 3.

Its linear nature and accurate representation of the solution for x solidify its position as the most suitable graph.