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A fish tank holds 180 gallons of water and is leaking at a rate of 8 gallons per day. A second fish tank holds 160 gallons of water and is leaking at a rate of 6 gallons per day. At how many days will the two fish tanks have the same amount of water?

1 Answer

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Answer:

10 days

Explanation:


180 - 8x = 160 - 6x

subtract 160 from both sides and add 8x to both sides


20 = 2x

divide both sides by 2


x = 10

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