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What is the percent composition of chlorine in C2H2Cl2? Solve to the correct number of significant figures.

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Answer:


\%Cl=73.13\%

Step-by-step explanation:

Hello.

In this case, we can compute the percent composition of chlorine as shown below:


\%Cl=(2*m_(Cl))/(M_(C_2H_2Cl_2))

Whereas the atomic mass of chlorine is 35.45 g/mol and the molar mass of C₂H₂Cl₂ is 96.95 g/mol, thus, the percent composition turns out:


\%Cl=(2*35.45g/mol)/(96.95g/mol)*100\%\\\\\%Cl=73.13\%

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User Kirill Shalnov
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