Question

[SCREENSHOT INCLUDED] The position of a particle moving along a coordinate plane is s = sqrt(1+5t), with s in meters and t and seconds. What is the particle's velocity when t = 3 sec?

Answer 1

C)
`(5)/(8)` m/s

Explanation:

`s(t)=√(1+5t)`

`v(t)=(d[s(t)])/(dt)`

`v(t)=(d(√(1+5t)))/(dt)`

`v(t)=(5)/(2√(1+5t))`

`v(3)=(5)/(2√(1+5(3)))`

`v(3)=(5)/(2√(1+15))`

`v(3)=(5)/(2√(16))`

`v(3)=(5)/(2(4))}`

`v(3)=(5)/(8)`

Therefore, the particle's velocity after 3 seconds is
`(5)/(8)` m/s.