Question

1 Javier has at most $15.00 to spend today. He buys a bag of pretzels and a bottle of juice for $2.59. If gasoline at this store costs $3.39 per gallon, how many gallons of gasoline, to the nearest tenth of gallon, can Javier buy for his car?​

Answer 1

3.7 gallons

Explanation:

15 - 2.59 = 12.41 (money left)

12.41 / 3.39 = 3.6607669...

3.6607669... → 3.7

Best of Luck!

Answer 2

Javier can buy at maximum about 3.7 gallons of oil.

Explanation:

Let g represent the amount of gasoline in galloons.

We know that Javier has at most $15.00 to spend. In other words, the total cost after buying the snacks and gasoline must be less than or equal to 15.

He already bought a snack and a drink for a total of $2.59.

And each gallon of gasoline costs $3.39.

So, we can write the following inequality:

`2.59+3.39g\leq 15.00`

To find how many galloons of gasoline Javier can buy, we will need to solve for g.

So, subtract 2.59 from both sides. This yields:

`3.39g\leq12.41`

Divide both sides by 3.39:

`g\leq3.66`

So, Javier can buy at maximum about 3.7 gallons of oil.

And we're done!