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Find the slope-intercept equation of the line
that passes through (5,0) and has a slope of 0

User Avanz
by
7.8k points

2 Answers

2 votes

A n s w e r

»»»»
\boxed{\boxed{\bf{y=0}}}

We are asked to find the slope intercept equation for a line that passes through (5,0) and has a slope of 0.

We'll use the point-slope formula for that.

Remember, point-slope is:


\bullet\qquad\rm{y-y_1=m(x-x_1)}

Substitute the values:


\large\begin{gathered}\sf{y-0=0(x-5)}\\\sf{y-0=0}\\\boxed{\sf{y=0}}\end{gathered}

User Jithesh Kt
by
7.9k points
6 votes

Answer:

y = 0

Explanation:

y = mx + b

if slope = 0 and passes through (5,0)

then

0 = 0(5) + b

b = 0

then y = 0

User Nikhil Kashyap
by
9.0k points

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