Question

A car starting from rest accelerates uniformly at 4.3 m/s^2 for 5.0 seconds. How far does the car move?

Answer 1

Vf = 21.5 [m/s]

Step-by-step explanation:

To solve this problem we must use the following kinematics equation:

`v_(f)= v_(i) +(a*t)\\`

where:

Vf = final velocity [m/s]

Vi = initial velocity = 0

a = aceleration = 4.3 [m/s^2]

t = time = 5 [s]

Now replacing:

Vf = 0 + (4.3*5)

Vf = 21.5 [m/s]