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A1 = 10 and an =an -1 +2

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I assume you're asking to solve for the n-th term in the sequence,
a_n.

From the given recursive rule,


a_n = a_(n-1) + 2 \implies a_(n-1) = a_(n-2) + 2

and by substitution,


\implies a_n = a_(n-2) + 2*2

Similarly,


a_n = a_(n-1) + 2 \implies a_(n-2) = a_(n-3) + 2


\implies a_n = a_(n-3) + 3*2

The pattern continues, so that we can write the n-th term in terms of the 1st one:


a_n = a_1 + (n-1)*2 \implies a_n = 10 + 2(n-1) = \boxed{2n+8}

So the first few terms of the sequence are

{10, 12, 14, 16, 18, 20, …}

User PypeBros
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