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Whats the distance rounded to the nearest tenth between the points (2, -2) and (6,3)

User Aloong
by
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1 Answer

4 votes

Answer:

The answer is 6.4 units

Explanation:

The distance between two points can be found by using the formula


d = \sqrt{ ({x1 - x2})^(2) + ({y1 - y2})^(2) } \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(2, -2) and (6,3)

The distance between them is


d = \sqrt{ ({2 - 6})^(2) + ({ - 2 - 3})^(2) } \\ = \sqrt{ ({ - 4})^(2) + ({ - 5})^(2) } \\ = √(16 + 25) \\ = √(41) \: \: \: \: \: \: \: \: \: \: \\ = 6.403124237...

We have the final answer as

6.4 units to the nearest tenth

Hope this helps you

User Marielouise
by
9.1k points

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