Question

Cise 5:

Yvette hangs a 24-N bird feeder in the middle of a rope tied between two


trees. The feeder creates a tension of 480 N in each side of the the rope.


a) If the two trees are 4.0 m apart, how much will the rope sag in the center?


b) If a bird lands on the feeder, will this have any effect on the tension in the


rope? Explain.

Answer 1

The answer is below

Step-by-step explanation:

a) Since the 24 N weight feeder creates a tension of 480 N on either side of the rope. Taking into consideration of one side of the rope, this means that 24/2 = 12 N creates a tension of 480 N for a length of 2 m (4/2).

Therefore, Fg = 12 N, F = 480 N

sin θ = Fg/F

sin θ = 12 / 480

sin θ = 0.025

θ = sin⁻¹ (0.025)

θ = 1.43⁰

Let the rope sag be h, hence:

tanθ = h/2 m

h = 2 m * tan (1.43)

h = 0.05 m

b) If the bird lands on the feeder, because of the birds weight, the tension on each side of the road would increase.