Question

Five times the smallest of three consecutive odd integers is seven more than twice the largest. Find the largest

integer.
// we also have to se only one variable to solve this equation.
like this x+3 would be okay

Answer 1

Answer: 9

Explanation:

Let the consecutive odd numbers be y, y+2 and y+4.

Five times the smallest of three consecutive odd integers is seven more than twice the largest. Find the largest integer can be expressed as:

5y = 2(y+4) + 7

5y = 2y + 8 + 7

5y = 2y + 15

5y - 2y = 15

y = 3

The smallest odd number is 5

The largest integer will be:

= y + 4

= 5+4

= 9