112k views
2 votes
Where is the vertex of y=3(x-26)^2+14?

User Pavelsaman
by
8.6k points

1 Answer

3 votes
The vertex is (26,14)

Because it’s written in vertex form which y=a(x-h)^2 + k. H is the x for the vertex And h is changed to it’s opposite. So since 26 is negative it would actually be positive 26. While k ls the y of the vertex which is 14 in our case
User Undefinederror
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories