187k views
3 votes
Write an equation of the line passing through the point (-7,-6) that is parallel to the line y=3x+2

User Molecule
by
5.2k points

1 Answer

4 votes

Answer: y = 3x+15

========================================================

Step-by-step explanation:

Parallel lines have equal slopes but different y intercepts.

The slope of y = 3x+2 is m = 3 (compare it to y = mx+b)

Any parallel line will also have slope m = 3

The parallel line goes through (x1,y1) = (-7, -6)

--------------------

Turn to point-slope form. Plug in the values mentioned and solve for y

y-y1 = m(x-x1)

y-(-6) = 3(x-(-7))

y+6 = 3(x+7)

y+6 = 3x+21

y = 3x+21-6

y = 3x+15

---------------------

Or you could use slope intercept form

y = mx+b

y = 3x+b

-6 = 3(-7)+b

-6 = -21+b

-6+21 = b

15 = b

b = 15

Since m = 3 and b = 15, we know the equation is y = 3x+15

User Zargony
by
5.3k points