Use the work-energy theorem. The total work W performed on the car as it it slows to a stop is equal to the change in the car's kinetic energy ∆K. So
W = ∆K
W = 0 - 1/2 (1000 kg) (72 km/h)²
W = - (500 kg) (20 m/s)²
W = - 200,000 J = -2 × 10⁵ J
The closest answer would be C, but friction opposes the car's motion so the work would be negative.