181k views
3 votes
Given f (x) = 17 minus x squared, what is the average rate of change in f(x) over the interval [1, 5]?

User Slymore
by
7.0k points

2 Answers

4 votes

Answer:

A: -6

Explanation:

User Haabda
by
6.7k points
6 votes

Answer:

The average rate of change of the function over the given interval is -6

Explanation:

The function we want to find its average rate of change is;

F(x) = 17 - x^2

Mathematically, the average rate of change of a function F(x) over an interval (a,b) can be calculated as;

{F(b) - F(a)}/(b-a)

According to this question, a = 1 and b = 5

F(a) = F(1) = 17 -(1)^2 = 17 -1 = 16

F(b) = F(5) = 17 - 5^2 = 17-25 = -8

So making the substitution; we have

(-8)-16/(5-1) = -24/4 = -6

User Gary Russell
by
6.2k points