Identify the center and radius of the circles: (x-4)^2+(y+4)^2 =4

Question

asked Jun 18, 2021 231k views

2 Answers

Lrxw · Answer 1 · 2021-06-20T20:21:44+0000

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Step-by-step explanation:

Rewrite the equation into (x-4)^2 + (y-(-4))^2 = 2^2

Compare this to (x-h)^2 + (y-k)^2 = r^2

We see that the center is (h,k) = (4,-4) and the radius is r = 2

Planestepper · Answer 2 · 2021-06-22T09:51:57+0000

Step-by-step explanation:

Hey there!

Given;

Tge equation of a circle is;

${(x - 4)}^(2) + ( {y + 4)}^(2) = 4$

Comparing it with (x-h)^2 + (y-k)^2= r^2 , we get;

h= 4

k = -4

And radius= 2 .

Therefore, the center is (4,-4) and radius is 2.

Hope it helps..