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A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation h(t) = –16t2 + 48t + 190.

What is the maximum height of the projectile?
A. 82 feet
B. 190 feet
C. 226 feet
D. 250 feet​

2 Answers

3 votes

Answer:

C. 226 feet

Explanation:

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User RoccoBerry
by
5.7k points
1 vote

Answer: C: 226ft

Step-by-step explanation:

User SeGa
by
5.4k points
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