Question

. Calculate the molarity of 2.00 L of a glucose solution that contains 582.0 g of glucose (C6H12O6).

Answer 1

`M=1.62M`

Step-by-step explanation:

Hello.

In this case, since the molarity is computed by the division of the moles of the solute by the volume of the solution in liters:

`M=(n_(solute))/(V_(solution))`

We first compute the moles of glucose (molar mass 180 g/mol) as shown below:

`n_(solute)=582.0g*(1mol)/(180g) =3.233mol`

Therefore, the molarity turns out:

`M=(3.233mol)/(2.00L)\\ \\M=1.62M`

Best regards.