Question

Find the distance between the two points rounding to the nearest tenth (if necessary),

(-1,-6) and (8,6)

Answer 1

Explanation:

Hey there!

The given points are; (-1-6) and (8,6).

Now, Using distance formula we get;

`d = \sqrt{ {(x2 - x1)}^(2) + ( {y2 - y1)}^(2) }`

Put all values.

`d = \sqrt{ {(8 + 1)}^(2) + ( {6 + 6)}^(2) }`

Simplify it to get answer.

`d = \sqrt{ {(9)}^(2) + ( {12)}^(2) }`

`d = √(81 + 144)`

`d = √(225)`

d = 15 units.

Therefore, the distance between two points is 15 units.

Hope it helps...

Answer 2

The answer is 15 units

Explanation:

The distance between two points can be found by using the formula

`d = \sqrt{ ({x1 - x2})^(2) + ({y1 - y2})^(2) } \\`

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-1,-6) and (8,6)

The distance between them is

`d = \sqrt{( { - 1 - 8})^(2) + ({ - 6 - 6})^(2) } \\ = \sqrt{ ({ - 9})^(2) + ( { - 12})^(2) } \\ = √(81 + 144) \\ = √(225) \: \: \: \: \: \: \: \: \: \: \\ = 15 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:`

We have the final answer as

15 units

Hope this helps you