Question

Anyone able to help me out? I don’t really understand this. Question 5&6

Answer 1

5. 200/1 = 200 ft/min

6. 600/3 = 200 ft/min

Explanation:

5. The rate of change of a graph is the ratio of vertical change to horizontal change. You are asked to find the rate of change from 1 minute to 2 minutes, so you want to find the distance (ft) at 2 minutes and at 1 minute.

Reading the graph, you see that at 2 minutes, the distance is 400 ft. At 1 minute, it is 200 ft.

So, the ratio of the two differences is ...

change in distance / change in time

`=(400-200)/(2-1)=(200)/(1)=200\quad\text{ft per min}`

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6. Using the same idea, we want to use the graph values at 4 minutes and 1 minute.

`\frac{\text{$\Delta$distance}}{\text{$\Delta$time}}=(800-200)/(4-1)=(600)/(3)=200\quad\text{ft per min}`