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At 235°C, the pressure of a sample of oxygen gas is 743 mm Hg. If the volume remains the same, what will the pressure be at 265°C?

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Answer:

786.88 mmHg

Step-by-step explanation:

From the question given above, the following data were obtained:

Initial temperature (T1) = 235 °C

Initial pressure (P1) = 743 mmHg

Volume = constant

Final temperature (T2) = 265 °C

Final pressure (P2) =..?

Next, we shall convert Celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T1) = 235 °C

Initial temperature (T1) = 235 °C + 273 = 508 K

Final temperature (T2) = 265 °C

Final temperature (T2) = 265 °C + 273 = 538 K

Finally, we shall determine the new pressure as illustrated below:

Initial temperature (T1) = 508 K

Initial pressure (P1) = 743 mmHg

Final temperature (T2) = 538 K

Final pressure (P2) =..?

P1/T1 = P2/T2

743/508 = P2/538

Cross multiply

508 × P2 = 743 × 538

508 × P2 = 399734

Divide both side by 508

P2 = 399734 / 508

P2 = 786.88 mmHg

Therefore, the new pressure of the gas is 786.88 mmHg

User Priyabrat Nanda
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