Question

Twice the sum of consecutive numbers n and n + 1 is 510. What is the smaller number?

Answer 1

The smaller number is 127

Explanation:

Lets write the given problem in equation form

sum of consecutive numbers n and n + 1 = n + n + 1 = 2n + 1

now we find twice of the sum of consecutive numbers n and n + 1

2*(2n + 1) = 4n + 2

given that

twice the sum of consecutive numbers n and n + 1 is 510

thus,

4n + 2 = 510

=> 4n = 510 -2 = 508

=> n = 508/4 = 127

Thus, the numbers are n = 127

n+1 = 127 + 1 = 128

the smaller number is 127